Get the complete 2023 WAEC Chemistry Practical May/June EXPO Room for School Candidates | WAEC May/June Chemistry 3 (Practical) (Alternative B (1st & 2nd Set) specimen Questions and Answers.
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Complete 2023 WAEC Chemistry Practical Questions And Answers
Monday, 19th June, 2023
Chemistry 3 (Practical) (Alternative B) – 09:30am – 11:30am (1st Set)
Chemistry 3 (Practical) (Alternative B) – 12:00pm – 2:00pm (2nd Set)
2023 WAEC CHEMISTRY PRACTICAL ALTERNATIVE B ANSWERS | 19TH JUNE, 2023
2023 WAEC Chemistry Practical (Alternative B) Questions and Answers :
No 1 ============================
For question 1
Use your school's endpoint and use it wherever you see our endpoint (20.4cm³) ...and calculate with it
Replace our 20.4 in 1bii and do the calculation.
If your school wants to use mine, then the chemistry teacher must submit endpoint similar to ours without much difference...eg 20.40, 20.45, 20.30, etc
Use your school's endpoint and use it wherever you see our endpoint (20.4cm³) ...and calculate with it
Replace our 20.4 in 1bii and do the calculation.
If your school wants to use mine, then the chemistry teacher must submit endpoint similar to ours without much difference...eg 20.40, 20.45, 20.30, etc
OR
(No2)===========================
(a) Observation: G dissolves completely in distilled water.
Conclusion: G is soluble in water.
(b)
(i) Observation: The litmus paper remains unchanged.
Conclusion: The solution is neutral, indicating that G is neither acidic nor basic.
(ii) Observation: The solution turns cloudy.
Conclusion: G reacts with NaOH to form a precipitate.
(iii) Observation: No visible reaction occurs.
Conclusion: G does not react with dilute HNO3.
(iv) Observation: A white precipitate forms.
Conclusion: G reacts with BaCl2 to form a precipitate in the presence of excess dilute HNO3.
(No 3a) ==========================
To determine the volume of water that should be added, we can use the formula for dilution:
M1V1 = M2V2
Where:
M1 = initial molarity of the solution
V1 = initial volume of the solution
M2 = final molarity of the solution
V2 = final volume of the solution
Given:
M1 = 0.5 mol/dm³
V1 = 100 cm³ (or 0.1 dm³)
M2 = 0.3 mol/dm³
V2 = ? (volume of water to be added)
Rearranging the formula, we have:
V2 = (M1 * V1) / M2
Substituting the given values, we get:
V2 = (0.5 mol/dm³ * 0.1 dm³) / (0.3 mol/dm³)
= (0.05 mol) / (0.3 mol/dm³)
= 0.1667 dm³
Therefore, approximately 0.1667 dm³ (or 166.7 cm³) of water should be added to 100 cm³ of 0.5 mol/dm³ HCl in order to obtain 0.3 mol/dm³ HCl.
(3b)
One possible chemical test to distinguish between dilute HCl and dilute HNO3 is to use silver nitrate (AgNO3) solution.
When a few drops of dilute HCl are added to a solution of AgNO3, no visible reaction occurs. However, when a few drops of dilute HNO3 are added to a solution of AgNO3, a white precipitate of silver chloride (AgCl) is formed.
The relevant equation for the reaction between dilute HNO3 and silver nitrate is:
HNO3 + AgNO3 -> AgCl + HNO3
The formation of the white precipitate of silver chloride indicates the presence of HNO3, while the absence of any reaction indicates the presence of HCl.
No 4 ============================
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2023 WAEC
CHEMISTRY PRACTICAL ALTERNATIVE A ANSWERS
(2b) 5.0
(3) USE YOUR SCHOOL'S TITLE VALUE HERE, NOTICE. Our school's titre value is shown below:
1. 16.50 2. 15.20 3. 15.10 Average: 15.15
YOR NUMBER 1 WILL BE MARKED BY WAEC USING THIS TEACHER'S FORM.
BE AWARE
regarding issue 1
Use your school's endpoint anywhere you see our endpoint (15.15cm3) and perform calculations using it.
Make the math using 15.15 in lieu of ours in 1b.
If your school wishes to utilize mine, the chemistry instructor must submit endpoints that are nearly identical to ours with only minor differences, such as 15.15, 15.20, 15.30, etc.
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